Wanderslost
Wanderslost t1_j20dwpj wrote
Reply to comment by ocelot08 in ELI5: How is that Pantone colors don't have direct RGB counterparts? by ExternalUserError
Is it possible to get 12 color wheels of Pantone colors that mimic specifice color spaces, such as traditional RBY, RGB, CMKY and even artistically pleasant (but theoretically unsound) spectrums?
I would prefer wheels that have different saturation in rings. I have spent a lot of time fiddling with photoshopping and pdfs of a Pantone swatch book. It has been interesting, but I have to believe this work has been done before.
Wanderslost t1_j20c5ok wrote
Reply to comment by TableGamer in ELI5: How is that Pantone colors don't have direct RGB counterparts? by ExternalUserError
I sell acrylic goods (dice). My manufacturer works in Pantone, specifically Pantone C. As far as I can tell, C is for surfaces, as opposed to photography and print.
I can attest that getting a spectrum of colors that is in your head translated to various color methods is much, much more nuanced than I expected.
Wanderslost t1_ir5pejx wrote
Excellent. It reminds me of the end of The Music of Erich Zann
Wanderslost t1_j20vrrv wrote
Reply to comment by ocelot08 in ELI5: How is that Pantone colors don't have direct RGB counterparts? by ExternalUserError
Thank you for your time.
I manufacture acrylic dice. I have 3 introductory (pantone C) colors that I just picked out because I liked them. The essence of my problem is I would like to offer 3 sets of 12 colors based off of these original colors. But I don't know how to pick the future pantones, though I have the original codes.
For bonus points. I thought it would be interesting if each set of 12 colors used a different color theory. However, I would settle for just making the house standard the painter's color wheels (ryb).
Not much translation needs to happen here. I provide the Pantone number, and they do it. The final product just needs to make sense with the dice already made. My comments above about pdfs and such was just a description of my (failed) attempts to figure this out.
Thanks again!